document.write( "Question 976823: Not understanding how to \"SIMPLIFY\" this; log9 1/729
\n" ); document.write( "(log nine, 1 over 729)
\n" ); document.write( "My answer options are; 3, 81, -81, -3
\n" ); document.write( "I would like to see the steps to get the correct answer. \n" ); document.write( "
Algebra.Com's Answer #598326 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"log%289%2C%281%2F729%29%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"log%28%281%2F729%29%29%2Flog%28%289%29%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"%28log%28%28+1%29%29-log%28%28729%29%29%29%2Flog%28%283%5E2%29%29\".......since \"log%28%28+1%29%29=0\", \"log%28%28729%29%29=log%283%5E6%29\" and \"log%28%289%29%29=log%28%283%5E2%29%29\", we have\r
\n" ); document.write( "\n" ); document.write( "=\"0-log%28%283%5E6%29%29%29%2Flog%28%283%5E2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"-6log%28%283%29%29%2F2log%28%283%29%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"-6cross%28log%28%283%29%29%29%2F2cross%28log%28%283%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"-6%2F2\"\r
\n" ); document.write( "\n" ); document.write( "=\"-3\"\r
\n" ); document.write( "\n" ); document.write( "so, your answer is \"-3\"\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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