document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=976810>Question 976810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the length of a side of a square is increased by 3 cm, the perimeter of the new square is 40 cm more than twice the length of the side of the original square. Find the length of the side of the original square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #598307 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=598307\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Side is X\r<BR>\n" );
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document.write( "Side increased by 3 is X+3\r<BR>\n" );
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document.write( "The perimeter, 4(X+3)=40+2X, now solve for X\r<BR>\n" );
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document.write( "4X+12=2X+40\r<BR>\n" );
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document.write( "2X=28\r<BR>\n" );
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document.write( "X=14\r<BR>\n" );
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document.write( "If increased to 17, the perimeter, 68, is 40 more than 28. Done.  </SPAN>\n" );
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