document.write( "Question 976787: Find three consecutive even numbers such that the sum of the first, one half of the second, and one fourth of the third is twenty less than twice the first. \n" ); document.write( "
Algebra.Com's Answer #598289 by FrankM(1040)\"\" \"About 
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3 even numbers can be written as\r
\n" ); document.write( "\n" ); document.write( "\"%282n%29%2B%282n%2B2%29%2B%282n%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2n%2B%281%2F2%29%282n%2B2%29%2B%281%2F4%29%282n%2B4%29=%284n-20%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2n%2B%28n%2B1%29%2B%281%2F4%29%282n%2B4%29=%284n-20%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283n%2B1%29%2B%281%2F4%29%282n%2B4%29=%284n-20%29\"\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides by 2 to get rid of that 1/4\r
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\n" ); document.write( "\n" ); document.write( "\"%286n%2B2%29%2B%28n%2B2%29=%288n-40%29\"\r
\n" ); document.write( "\n" ); document.write( "\"7n%2B4=8n-40\"\r
\n" ); document.write( "\n" ); document.write( "\"0=n-44\"\r
\n" ); document.write( "\n" ); document.write( "\"n=44\"\r
\n" ); document.write( "\n" ); document.write( "The numbers are\r
\n" ); document.write( "\n" ); document.write( "88,90,92\r
\n" ); document.write( "\n" ); document.write( "the sum of the first (88), one half of the second (45), and one fourth of the third (23) (total 156) is twenty less than twice the first (176-20)
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