document.write( "Question 976705: Find the distance between the pair of parallel lines, y = -2x+1 & y = -2x+16. \n" ); document.write( "
Algebra.Com's Answer #598267 by lwsshak3(11628)\"\" \"About 
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Find the distance between the pair of parallel lines, y = -2x+1 & y = -2x+16. (slope,m=-2)
\n" ); document.write( "equation of a line perpendicular to pair of given lines: y=x/2 (slope,m=1/2)
\n" ); document.write( "Point of intersection between perpendicular line and one of the parallel lines:
\n" ); document.write( "x/2=-2x+1
\n" ); document.write( "x=-4x+2
\n" ); document.write( "5x=2
\n" ); document.write( "x=2/5
\n" ); document.write( "y=1/5
\n" ); document.write( "point of intersection: (2/5,1/5)
\n" ); document.write( "..
\n" ); document.write( "Point of intersection between perpendicular line and other parallel line:
\n" ); document.write( "x/2=-2x+16
\n" ); document.write( "x=-4x+32
\n" ); document.write( "5x=32
\n" ); document.write( "x=32/5
\n" ); document.write( "y=32/10=16/5
\n" ); document.write( "point of intersection: (32/5,16/5)
\n" ); document.write( "..
\n" ); document.write( "Use distance formula to find the distance between the 2 points of intersection
\n" ); document.write( "d=√(x1-x2)^+(y1-y2)^2)=√(32/5-2/5)^2+(16/5-(1/5)^2=√(36+9)=√45
\n" ); document.write( "distance between the pair of parallel lines=√45 \n" ); document.write( "
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