document.write( "Question 976230: How to prove this following identity?
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document.write( "(sin2x+cos2x)/(2cosx+sinx-2(cos^3x+sin^3x))=cosecx \n" );
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Algebra.Com's Answer #598227 by FrankM(1040)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "First, the sum of cubes \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This applies to the denominator \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "but you see the sin squared and cos squared add to 1? \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify denominator a bit more to get:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note that \n" ); document.write( "\n" ); document.write( "and if we factor a sin out of the first two terms in denominator we get: \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and can make the substitution:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next we have \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so let's factor sin out of the later part of denominator\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and make the substitution\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now, factor out sin in the denominator:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And after canceling numerator/denominator all we have left is \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "which is cosecant.\r \n" ); document.write( "\n" ); document.write( "There may be a faster or more elegant method, but it's key to see that the sum of two cubes had to be factored to start the process. \n" ); document.write( " |