document.write( "Question 11602: In preparation for a party, Heather fills a large jar with gum drops. Before the party begins, Michael see the gum drop jar. He (hoping that no one will realize) takes one-third of the drops. Soon after, Tanya takes one-third of the gum drops (she too hopes that nobody will notice). Finally, Brian appears and, like the others, takes one-third of the gum drops. If forty gum drops are left in the jar, how many did it originally contain? \n" ); document.write( "
Algebra.Com's Answer #5982 by Earlsdon(6294)\"\" \"About 
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Let x = the original number of jelly beans in the jar before the pilfering began.\r
\n" ); document.write( "\n" ); document.write( "After Michael has pinched his third, the number left is:\r
\n" ); document.write( "\n" ); document.write( "\"x+-+%281%2F3%29x+=+%282%2F3%29x\"\r
\n" ); document.write( "\n" ); document.write( "After Tanya's sampling, the number left is:\r
\n" ); document.write( "\n" ); document.write( "\"%282%2F3%29x+-+%281%2F3%29%282%2F3%29x+=+%286%2F9%29x+-+%282%2F9%29x\" = \"%284%2F9%29x\"\r
\n" ); document.write( "\n" ); document.write( "Finally, after Brian has helped himself to one third, there are 40 jelly beans remaining:\r
\n" ); document.write( "\n" ); document.write( "\"%284%2F9%29x+-+%281%2F3%29%284%2F9%29x+=+%2812%2F27%29x+-+%284%2F27%29x\"\r
\n" ); document.write( "\n" ); document.write( "\"%288%2F27%29x+=+40\" Multiply both sides by 27.\r
\n" ); document.write( "\n" ); document.write( "\"8x+=+1080\" Divide both sides by 8.\r
\n" ); document.write( "\n" ); document.write( "\"x+=+135\" There were 135 jelly beans in the jar before the crime.\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"135+-+135%2F3+=+135+-+45\" = 90
\n" ); document.write( "\"90+-+90%2F3+=+90+-+30\" = 60
\n" ); document.write( "\"60+-+60%2F3+=+60+-+20\" = 40
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