document.write( "Question 976564: Peter paddled a canoe 20 miles upstream, then paddled the canoe back to the starting point. the rate of the current was 3 mph and the total trip took 7 hours. At what rate would Peter paddle the canoe in still water?\r
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document.write( "Please help solve.
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Algebra.Com's Answer #598135 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Peter paddled a canoe 20 miles upstream, then paddled the canoe back to the starting point. the rate of the current was 3 mph and the total trip took 7 hours. At what rate would Peter paddle the canoe in still water? \n" ); document.write( "*** \n" ); document.write( "let x=rate in still water \n" ); document.write( "x+3=rate of canoe downtream \n" ); document.write( "x-3=rate of canoe uptream \n" ); document.write( "travel time=distance/rate \n" ); document.write( " \n" ); document.write( "lcd: (x+3)(x-3) \n" ); document.write( "20(x-3)+20(x+3)=7(x+3)(x-3) \n" ); document.write( "20x-60+20x+60=7(x^2-9) \n" ); document.write( "40x=7x^2-63 \n" ); document.write( "7x^2-40x-63=0 \n" ); document.write( "(x-7)(7x+9)=0 \n" ); document.write( "x=-9/7(reject) \n" ); document.write( "x=7 \n" ); document.write( "At what rate would Peter paddle the canoe in still water? 7 mph \n" ); document.write( " |