document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=976365>Question 976365</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Roberto invested some money at 2.75%, and then invested $2000 more than twice this amount at 3%.  His total annual income from the two investments was $1197.50.  How much did he invest at 3%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #598133 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=598133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Roberto invested some money at 2.75%, and then invested $2000 more than twice this amount at 3%. His total annual income from the two investments was $1197.50. How much did he invest at 3%?<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=amt invested at 2.75%<BR>\n" );
document.write( "2x+3000=amt invested at 3.00%<BR>\n" );
document.write( "..<BR>\n" );
document.write( ".0275x+.03(2x+2000)=1197.50<BR>\n" );
document.write( ".0275x+.06x+60=1197.50<BR>\n" );
document.write( ".0875x=1137.50<BR>\n" );
document.write( "x=13000<BR>\n" );
document.write( "2x+3000=29000<BR>\n" );
document.write( "How much did he invest at 3%? $29,000 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );