document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83299>Question 83299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with the following equation:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-12a%5E5b%5E-2%2F4a%5E-3b%5E7 ALIGN=MIDDLE  ALT=\"-12a%5E5b%5E-2%2F4a%5E-3b%5E7\"   DISABLED_style= \"max-width:90%; height:auto;\" >^-3 I am just confused as to what to do with the base. Do I raise the base to the 3rd root, or just multiply it? Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59806 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> [(-12a^5b^-2) / (4a^-3b^7)]^-3 <BR>\n" );
document.write( "-------<BR>\n" );
document.write( "=[-3a^8/b^9)]^-3<BR>\n" );
document.write( "Comment: The 3 in the exponent means we should cube each factor; the negative<BR>\n" );
document.write( "means we should invert the result.\r<BR>\n" );
document.write( "\n" );
document.write( "=[-b^27/27a^24]<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );