document.write( "Question 976441: using the integral calculus to solve a simple engineering question,\r
\n" ); document.write( "\n" ); document.write( "a missile is accelerating at a rate of 6 t m/sec^2 from a position at rest in a silo 40m above ground level. how high above the ground will it be after 4 seconds
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Algebra.Com's Answer #598014 by Alan3354(69443)\"\" \"About 
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a missile is accelerating at a rate of 6t m/sec^2 from a position at rest in a silo 40m above ground level. how high above the ground will it be after 4 seconds
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\n" ); document.write( "40 meters above ground? Most are below ground.
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\n" ); document.write( "Accel = 1st derivative of speed = 2nd derivative of displacement.
\n" ); document.write( "a = 6t (assuming t is time in seconds)
\n" ); document.write( "Using its starting height as zero at t = 0:
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\n" ); document.write( "INT(6t) = 3t^2 + C
\n" ); document.write( "C = 0
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\n" ); document.write( "INT(3t^2) = t^3 + C
\n" ); document.write( "Again, C = 0
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\n" ); document.write( "s = t^3
\n" ); document.write( "At t = 4, s = 64 meters
\n" ); document.write( "Add or subtract the 40 meters
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