document.write( "Question 1749: Find the solution sets of the following equation: x+1/y+1=2
\n" ); document.write( " 2x+1/2y+1=1/3
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Algebra.Com's Answer #598 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
equation 1 re-arranges to \"%28x%2B1%29+=+2%28y%2B1%29\" and then to \"%28x%2B1%29+=+%282y%2B2%29\" and finally to \"x-2y+=+1\".\r
\n" ); document.write( "\n" ); document.write( "equation 2 re-arranges to \"3%282x%2B1%29+=+%282y%2B1%29\" and then to \"%286x%2B3%29+=+2y%2B1\" and finally to \"6x-2y=-2\".\r
\n" ); document.write( "\n" ); document.write( "We now have a set of simulataneous linear equations...subtract them, to get rid of the -2y term. This gives \"x=%28-3%29%2F5\"\r
\n" ); document.write( "\n" ); document.write( "Substitute this into one of the 2 equations gives \"y=%28-4%29%2F5\"\r
\n" ); document.write( "\n" ); document.write( "Now check in the other equation, that these 2 values do indeed equal the right hand side number...they do, but check it yourself.\r
\n" ); document.write( "\n" ); document.write( "cheers
\n" ); document.write( "Jon.
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