document.write( "Question 976391: A is chasing B. They are separated by 18 miles and A is traveling at 300 mph and B is traveling at 240 mph. If the aircraft fly for 7 minutes, how far behind is A? \n" ); document.write( "
Algebra.Com's Answer #597976 by josgarithmetic(39626)\"\" \"About 
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A, B, aircraft,... what?\r
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\n" ); document.write( "\n" ); document.write( "Give the full problem description and question.\r
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\n" ); document.write( "\n" ); document.write( "(Enough now understood)
\n" ); document.write( "The description does not say, \"catch up\"; but only asks what is their separation in distance after 7 minutes.\r
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\n" ); document.write( "\n" ); document.write( "___________________rate___________time__________distance
\n" ); document.write( "craftA_____________300_____________7____________\"A\"
\n" ); document.write( "craftB_____________240_____________7____________\"B\"\r
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\n" ); document.write( "\n" ); document.write( "A and B are also being used in this solution as the distances gone, for each aircraft. Note that you can make a number line to show the relative initial positions of craft A and craft B.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28A=300%2A7=2100%2CB=240%2A7=1680%29\".\r
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\n" ); document.write( "\n" ); document.write( "Zero on the number line is where A starts. 18 on the number line is where B starts. Each goes in the same direction, toward the greater values of the number line.\r
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\n" ); document.write( "\n" ); document.write( "aircraft A: went 2100 miles ON THE NUMBER LINE.
\n" ); document.write( "aircraft B: went to 1680+18=1698 ON THE NUMBER LINE, since it started AT 18.\r
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\n" ); document.write( "\n" ); document.write( "The separation now is that A is AHEAD of B by 2100-1698=402 miles.\r
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