document.write( "Question 976308: linda invested $12,000 for one year, part at 12 percent annual interest and the rest at 6 percent annual interest. how much did she invest at 6 percent to get $1,200 interest in a year? \n" ); document.write( "
Algebra.Com's Answer #597917 by FrankM(1040)\"\" \"About 
You can put this solution on YOUR website!
X is invested at 12%\r
\n" ); document.write( "\n" ); document.write( "12000-X is invested at 6%\r
\n" ); document.write( "\n" ); document.write( ".12X + .06(12000-X) = 1200\r
\n" ); document.write( "\n" ); document.write( ".12X + 720 - .06X = 1200\r
\n" ); document.write( "\n" ); document.write( ".06X = 480\r
\n" ); document.write( "\n" ); document.write( "X = $8000 ($960 interest from this portion)\r
\n" ); document.write( "\n" ); document.write( "12000-X = $4000 ($240 interest from this portion)\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );