document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=976215>Question 976215</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A lot is in the shape of a right triangle.  The shorter leg measures 150 m.  The hypotenuse is 50 m longer than the length of the longer leg.  How long is the longer leg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597888 by </B><A HREF=/tutors/aboutme.mpl?userid=Loon+Bajracharya><B>Loon Bajracharya(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Loon+Bajracharya><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the shorter leg be the perpendicular and the longer leg be base.<BR>\n" );
document.write( "by using Pythagorean theoream,we have\r<BR>\n" );
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document.write( "h^2=p^2+b^2<BR>\n" );
document.write( "now,if the hypotenious is 50m longer than longer i.e base. then h=p+50m\r<BR>\n" );
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document.write( "therefore,\r<BR>\n" );
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document.write( "(p+50m)^2=p^2+150^2\r<BR>\n" );
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document.write( "now fore the hypotenious side solve using the formula (a+b)^2\r<BR>\n" );
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document.write( "p^2+2×p×50+50^2=p^2+22500\r<BR>\n" );
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document.write( "or,100p=p^2-p^2+22500-2500<BR>\n" );
document.write( "or,p=20000/100\r<BR>\n" );
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document.write( "therefore, p=longer leg=200m\r<BR>\n" );
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document.write( "SOLVED..... </SPAN>\n" );
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