document.write( "Question 976187: Fred averaged 58 mph on his way to the Rose Bowl. On his way back he traveled at 50 mph but took 64 minutes longer. What was the distance of his route? \n" ); document.write( "
Algebra.Com's Answer #597878 by ankor@dixie-net.com(22740)\"\" \"About 
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Fred averaged 58 mph on his way to the Rose Bowl.
\n" ); document.write( " On his way back he traveled at 50 mph but took 64 minutes longer.
\n" ); document.write( " What was the distance of his route?
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\n" ); document.write( "Let d = the one-way distance of trip
\n" ); document.write( "Since we are dealing in mph, change 64 min to hrs. 64/60 = 1.0667 hrs
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\n" ); document.write( "Write a time equation, time = dist/speed
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\n" ); document.write( "return time = to time + 64 min (1.0667 hrs)
\n" ); document.write( "\"d%2F50\" = \"d%2F58\" + 1.0667
\n" ); document.write( "multiply by 50*58=2900, cancel the denominators
\n" ); document.write( "58d = 50d + 2900(1.0667)
\n" ); document.write( "58d - 50d = 3093.43
\n" ); document.write( "8d = 3093.43
\n" ); document.write( "d = 3093.43
\n" ); document.write( "d = 386.68 miles is the one-way distance
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\n" ); document.write( "See if that checks out find the actual time each way
\n" ); document.write( "386.68/50 = 7.73 hrs
\n" ); document.write( "386.68/58 = 6.67
\n" ); document.write( "------------------
\n" ); document.write( "time differ: 1.06 hrs which is 1.06(60) = 63.6 ~ 64 min \n" ); document.write( "
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