document.write( "Question 976218: In the morning, Maria drove to an appointment at 50mph. Her average speed on the return trip in the afternoon was 40 mph. The return trip took 1/10 hour longer. How far did she travel to the appointment? \n" ); document.write( "
Algebra.Com's Answer #597855 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
x = distance from home to appointment\r
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\n" ); document.write( "\n" ); document.write( "Morning:
\n" ); document.write( "d = r*t
\n" ); document.write( "x = 50*t
\n" ); document.write( "t = x/50
\n" ); document.write( "It takes her x/50 hours to drive x miles in the morning at 50 mph\r
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\n" ); document.write( "\n" ); document.write( "Afternoon:
\n" ); document.write( "d = r*t
\n" ); document.write( "x = 40*t
\n" ); document.write( "t = x/40
\n" ); document.write( "It takes her x/40 hours to drive x miles in the afternoon at 40 mph\r
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\n" ); document.write( "\n" ); document.write( "\"The return trip took 1/10 hour longer\", so that means\r
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\n" ); document.write( "\n" ); document.write( "(return trip time) = (time to get to appointment)+(1/10 of an hour)
\n" ); document.write( "x/40 = (x/50) + (1/10)
\n" ); document.write( "x/40 = (x/50) + (1/10)*(5/5)
\n" ); document.write( "x/40 = (x/50) + (5/50)
\n" ); document.write( "x/40 = (x+5)/50
\n" ); document.write( "50x = 40(x+5)
\n" ); document.write( "50x = 40x+200
\n" ); document.write( "50x-40x = 200
\n" ); document.write( "10x = 200
\n" ); document.write( "x = 200/10
\n" ); document.write( "x = 20\r
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\n" ); document.write( "\n" ); document.write( "Summary:
\n" ); document.write( "x = 20
\n" ); document.write( "The distance from home to the appointment is 20 miles\r
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\n" ); document.write( "\n" ); document.write( "Jim\r
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