document.write( "Question 976204: A jet takes
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\n" ); document.write( " against the wind. The return trip takes
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Algebra.Com's Answer #597853 by t0hierry(194)\"\" \"About 
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against the wind: speed jet = speed without wind - speed wind
\n" ); document.write( "with the wind speed jet = speed w/o wind + speed wind\r
\n" ); document.write( "\n" ); document.write( "time = distance/speed = d/(s-w) = 6h
\n" ); document.write( "time return - d/(s + w) = 5h\r
\n" ); document.write( "\n" ); document.write( "so 6*(s-w) = 5 (s+w)
\n" ); document.write( "s = 11 w\r
\n" ); document.write( "\n" ); document.write( "so s-w = 10w = d/6 = 4860/6 = 810 which gives \r
\n" ); document.write( "\n" ); document.write( "w = 81 mph
\n" ); document.write( "s= 891 mph
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