document.write( "Question 976204: A jet takes
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document.write( "6
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document.write( " hours to travel a distance of
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document.write( "4860mi
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document.write( " against the wind. The return trip takes
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document.write( "5
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document.write( "hours with the wind. What is the rate of the jet in still air and what is the rate of the wind? \n" );
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Algebra.Com's Answer #597853 by t0hierry(194) You can put this solution on YOUR website! against the wind: speed jet = speed without wind - speed wind \n" ); document.write( "with the wind speed jet = speed w/o wind + speed wind\r \n" ); document.write( "\n" ); document.write( "time = distance/speed = d/(s-w) = 6h \n" ); document.write( "time return - d/(s + w) = 5h\r \n" ); document.write( "\n" ); document.write( "so 6*(s-w) = 5 (s+w) \n" ); document.write( "s = 11 w\r \n" ); document.write( "\n" ); document.write( "so s-w = 10w = d/6 = 4860/6 = 810 which gives \r \n" ); document.write( "\n" ); document.write( "w = 81 mph \n" ); document.write( "s= 891 mph \n" ); document.write( " |