document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=976210>Question 976210</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.<BR>\n" );
document.write( "Event A: The sum is greater than 8.<BR>\n" );
document.write( "Event B: The sum is an odd number.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597852 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597852\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the probability of each number is<BR>\n" );
document.write( "2=1/36\r<BR>\n" );
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document.write( "6=5/36<BR>\n" );
document.write( "7=6/36<BR>\n" );
document.write( "8=5/36\r<BR>\n" );
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document.write( "12=1/36\r<BR>\n" );
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document.write( "Probability >8 = (4+3+2+1)/36=10/36=5/18\r<BR>\n" );
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document.write( "Odd number (2+4+6+4+2)=18/36=(1/2) </SPAN>\n" );
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