document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=976209>Question 976209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove the identity:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28x%29%2F%281-sin%28x%29%29+%2B+cos%28x%29%2F%281%2Bsin%28x%29%29+=+2%2A%28%281%2Btan%5E2%28x%29%29%2Fsec%28x%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597849 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> term on left over (1-sinx^2)\r<BR>\n" );
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document.write( "{cos x(1-sinx) +cos x(1+sinx)}/1-sinx^2\r<BR>\n" );
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document.write( "cos x-cosx sinx + cosx+ cosx sinx=2cosx<BR>\n" );
document.write( "1-sinx^2=cosx^2\r<BR>\n" );
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document.write( "(2cosx)/(cosx^2) =2/cos x\r<BR>\n" );
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document.write( "term on right:  tanx^2+ 1=secx^2.     {sinx^2/cosx^2} +1 ={sinx^2+cosx^2/cosx^2} = 1/cosx^2=secx^2.\r<BR>\n" );
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document.write( "secx^2/sec x=sec x = 1/cos x\r<BR>\n" );
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document.write( "2* (1/cosx)= 2/cosx\r<BR>\n" );
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