document.write( "Question 976140: 1/cosA+sinA+1 + 1/cosA+sinA-1 is equal to cosecA+secA how to prove it. \n" ); document.write( "
Algebra.Com's Answer #597800 by josgarithmetic(39625) ![]() You can put this solution on YOUR website! Start with the more complicated expression and simplify. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You have obvious other simplifications to do first. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplest common denominator is cos(A).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "This appears not to be same as cosec(A)+sec(A).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Try starting with the other expression instead. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Much work done so far, but the identity is not proved, and it is likely not an identity. \n" ); document.write( " |