document.write( "Question 83248: Help me please! A coffee and tea shop wishes to blend a $3.50-per-pound coffee with a $4.75-per-pound coffee in order to produce a $4-per-pound blend. How much of each would hve to be used to produce 100 pounds of the nw blend? \n" ); document.write( "

Algebra.Com's Answer #59780 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x=amount of 3.50 coffee\r
\n" ); document.write( "\n" ); document.write( "Then 100-x=amount of 4.75 coffee\r
\n" ); document.write( "\n" ); document.write( "Now we know that the total cost of the 3.50 coffee (3.50x) plus the total cost of the 4.75 coffee(4.75)(100-x) must equal the total cost of the final mixture (4.00(100)). So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "3.50x+4.75(100-x)=4.00(100) get rid of parens\r
\n" ); document.write( "\n" ); document.write( "3.50x+475-4.75x=400 subtract 475 from both sides\r
\n" ); document.write( "\n" ); document.write( "3.50x+474-475-4.75x=400-475 collect like terms\r
\n" ); document.write( "\n" ); document.write( "-1.25x=-75 divide both sides by -1.25
\n" ); document.write( "x=60 lbs -------------------------------amount of 3.50 coffee\r
\n" ); document.write( "\n" ); document.write( "100-x=100-60=40 lb------------------------amount of 4.75 coffee\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "3.50(60)+4.75(40)=4.00(100)
\n" ); document.write( "210+190=400
\n" ); document.write( "400=400\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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