document.write( "Question 976137: A spherical weather balloon is being inflated. The radius of the balloon is increasing at the rate of 3 cm per second. Express the surface area of the balloon as a function of time t (in seconds). If needed you can enter \pi as pi. Recall surface area of a sphere is 4*pi*r^2 .\r
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Algebra.Com's Answer #597798 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"A=4pi%2Ar%5E2\", your surface area formula, variable being r.\r
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\n" ); document.write( "\n" ); document.write( "\"dA%2Fdt=4pi%2A2r%2A%28dr%2Fdt%29\"
\n" ); document.write( "\"dA%2Fdt=8pi%2Ar%28dr%2Fdt%29\"
\n" ); document.write( "Chain Rule is used because radius r is a function of time, and using t for time variable.\r
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\n" ); document.write( "\n" ); document.write( "Your example specifically specified, \"dr%2Fdt=3\", in cm squared per second.
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