document.write( "Question 976056: find the roots of the polynomial
\n" ); document.write( "p(x) = x^4+4x^3+6x^2+4x+5=0 given that one of the roots is x= -i
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Algebra.Com's Answer #597753 by josgarithmetic(39627)\"\" \"About 
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Another root is x=i, because complex roots for polynomial functions come as conjugate pairs. Those two roots are as \"%28x-%28-i%29%29%28x-i%29=%28x-i%29%28x%2Bi%29\"
\n" ); document.write( "\"x%5E2-i%5E2\"
\n" ); document.write( "\"x%5E2-%28-1%29\"
\n" ); document.write( "\"highlight_green%28x%5E2%2B1%29\", a factor of the polynomial p(x).\r
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\n" ); document.write( "\n" ); document.write( "Use polynomial division for \"x%5E4%2B4x%5E3%2B6x%5E2%2B4x%2B5\" as dividend
\n" ); document.write( "and \"x%5E2%2B1\" as divisor. The quotient represents the rest of the factors, as quadratic, degree two.
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\n" ); document.write( "The division process not shown here; but result is \"x%5E2%2B4x%2B5\" as the quotient.\r
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\n" ); document.write( "\n" ); document.write( "Use general solution method for a quadratic equation to find the zeros of this factor:
\n" ); document.write( "roots are
\n" ); document.write( "\"x=%28-4%2B-+sqrt%284%5E2-4%2A5%29%29%2F2\"
\n" ); document.write( "\"x=%28-4%2B-+sqrt%28-4%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%28-4%2B-+2i%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=-2%2B-+i%29\" or -2-i and -2+i.\r
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\n" ); document.write( "\n" ); document.write( "(along with -i and i ).
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