document.write( "Question 83124This question is from textbook Enementary and Intremediate Algebra
\n" ); document.write( ": page 140 problem 34\r
\n" ); document.write( "\n" ); document.write( "Cost of Road Service Ricks Automotive charges $50.00 plus $15.00 for each (15 min.)unit of time when making a road call. Twin City Repair charges $70.00 plus $10.00 for each unit of time. Under what circumstances would it be more economical for a motorist to call Ricks?
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Algebra.Com's Answer #59775 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Let t= number of units of time needed for the road call\r
\n" ); document.write( "\n" ); document.write( "Now we know that it would be more economical to use Rick's if the total cost of the road call is less than Twin City\r
\n" ); document.write( "\n" ); document.write( "So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "50+15t<70+10t subtract 10t and also 50 from both sides\r
\n" ); document.write( "\n" ); document.write( "50-50+15t-10t<70-50+10t-10t collect like terms\r
\n" ); document.write( "\n" ); document.write( "5t<20 divide both sides by 5\r
\n" ); document.write( "\n" ); document.write( "t<4 units of time, in other words, if the road call takes less than an hour it would be more economical to use Rick's\r
\n" ); document.write( "\n" ); document.write( "Clearly, if t=4 units of time, then the two would cost the same
\n" ); document.write( "50+60=70+40
\n" ); document.write( "110=110
\n" ); document.write( "Hope this helps------ptaylor\r
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