document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=976086>Question 976086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I know there is alot of similar questions, but I couldn't find the answer to this challenge offered by my teacher..\r<BR>\n" );
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document.write( "Nick can paint a fence by himself in 6 hours. When he works with his brother James they can paint a fence in 4 hours. How long would it take James to paint a fence by himself? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597735 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597735\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a day (24 hours) Nick paints 4 fences. <BR>\n" );
document.write( "In a day James and Nick paint 6 fences. \r<BR>\n" );
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document.write( "Nick still paints 4 fences in a day, so James painted 2. James takes 12 hours per fence. \r<BR>\n" );
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document.write( "The above is a fool proof method to solve this problem, but it lacks the algebra type of set up the teacher might like. \r<BR>\n" );
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document.write( "Nick's rate is 1/6 fence per hour. This is key, as hours per fence will not work.  \r<BR>\n" );
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document.write( "Nick + James' combined rate is 1/4 fence per hour.\r<BR>\n" );
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document.write( "1/6 + X = 1/4\r<BR>\n" );
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document.write( "4/24 + X = 6/24\r<BR>\n" );
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document.write( "X = 2/24, i.e. James' rate is 1 fence per 12 hours.  </SPAN>\n" );
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