document.write( "Question 976044: If \"+log%283%2CN%29+=+x\" and \"+log%2815%2CN%29+=+y\", prove that \"log%2845%2C5%29+=+%28x-y%29%2F%28x%2By%29\"
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Algebra.Com's Answer #597723 by JoelSchwartz(130)\"\" \"About 
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3^x=N
\n" ); document.write( "15^y=N
\n" ); document.write( "3^x=15^y
\n" ); document.write( "3^(x/y)=15
\n" ); document.write( "10^(log(3))=3
\n" ); document.write( "10=3^(1/(log(3)))
\n" ); document.write( "10^(log(15))=15
\n" ); document.write( "(3^(1/(log(3))))^(log(15)=15
\n" ); document.write( "3^((log(15))/(log(3)))=15
\n" ); document.write( "x/y=(log(15))/(log(3))
\n" ); document.write( "x=log(15)
\n" ); document.write( "y=log(3)
\n" ); document.write( "45^((log(15)-log(3))/(log(15)+log(3)))=5
\n" ); document.write( "45^((log(5))/(log(45)))=5
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