document.write( "Question 976063: solve the equation by the use of substitution method showing all the steps taken in solving equation;\r
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Algebra.Com's Answer #597719 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The other tutor didn't use the substitution method but used the \r\n" );
document.write( "addition (elimination) method.  Even though it's easier here, one\r\n" );
document.write( "must follow instructions.  Here's the substitution method:\r\n" );
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\n" ); document.write( "solve the equation by the use of substitution method showing all the steps taken
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document.write( "Get rid of the fractions first by muyltiplying the first equation\r\n" );
document.write( "through by the LCD of 10 and the second one through by the LCD of 12\r\n" );
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document.write( "\"system%284x%2B15y=20%2C28x-15y=-60%29\"\r\n" );
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document.write( "Solve the first equation for 4x = 20-15y\r\n" );
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document.write( "Then since 28x is 7*4x, replace 28x by 7(20-15y) in the second equation:\r\n" );
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document.write( "      28x-15y = -60\r\n" );
document.write( "7(20-15y)-15y = -60\r\n" );
document.write( " 140-105y-15y = -60\r\n" );
document.write( "     140-120y = -60\r\n" );
document.write( "        -120y = -200\r\n" );
document.write( "            y = 5/3\r\n" );
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document.write( "Substitute in \r\n" );
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document.write( "           4x = 20-15y\r\n" );
document.write( "           4x = 20-15(5/3)\r\n" );
document.write( "           4x = 20-25\r\n" );
document.write( "           4x = -5\r\n" );
document.write( "            x = -5/4\r\n" );
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document.write( "Edwin
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