document.write( "Question 975956: Find the half-life to the nearest tenth of a year of a radioactive substance that decays from 65 mg to 17.55 mg in 20years according to the exponential decay model y = ae^−bx where a is the initial amount and y is the amount remaining after x years. \n" ); document.write( "
Algebra.Com's Answer #597698 by josgarithmetic(39628)\"\" \"About 
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\"y=a%2Ae%5E%28-bx%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28y%29=ln%28a%29-bx\"
\n" ); document.write( "\"ln%28y%29-ln%28a%29=-bx\"
\n" ); document.write( "\"ln%28a%2Fy%29=bx\"
\n" ); document.write( "\"b=%281%2Fx%29ln%28a%2Fy%29\"\r
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\n" ); document.write( "\n" ); document.write( "VALUE OF b:
\n" ); document.write( "\"%281%2F20%29ln%2865%2F17.55%29\"
\n" ); document.write( "\"highlight%28b=0.06547%29\"\r
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\n" ); document.write( "\n" ); document.write( "FIND HALF-LIFE:
\n" ); document.write( "\"ln%28a%2Fy%29=bx\", from earlier step,
\n" ); document.write( "\"x=%281%2Fb%29ln%28a%2Fy%29\"
\n" ); document.write( "\"x=%281%2F0.06547%29ln%281%2F%281%2F2%29%29\"
\n" ); document.write( "\"highlight%28x=%281%2F0.06547%29ln%282%29%29\"
\n" ); document.write( "-----That will be the half-life. You can finish computing it.
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