document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=976000>Question 976000</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the sum of the first 12 terms of the geometric sequence 2, 6, 18, 54,.... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597685 by </B><A HREF=/tutors/aboutme.mpl?userid=Iambibek1><B>Iambibek1(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Iambibek1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597685\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here,<BR>\n" );
document.write( "1st term(a)=2<BR>\n" );
document.write( "common ratio(r)=t2/t1=3<BR>\n" );
document.write( "So,We have,<BR>\n" );
document.write( "Sn=a(r^(n-1))/(r-1)<BR>\n" );
document.write( "S12={2(3^(12-1)}/(3-1)<BR>\n" );
document.write( "By solving this we can get sum of 12 terms=3^11 </SPAN>\n" );
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