document.write( "Question 83259: Could you please find the area bounded by the curve [0, $\"pi\"$ ] of f(x) = sin(x) using antiderivatants? \n" ); document.write( "

Algebra.Com's Answer #59765 by Nate(3500) $\"\"$ $\"About$

You can put this solution on YOUR website!
f(x) = sin(x) is actually: A(x) = f'(x) = sin(x) where as A(x) is the area
\n" ); document.write( " $\"int%28+sin%28x%29%2C+dx%2C+0%2C+pi+%29+=+-cos%28x%29\"$
\n" ); document.write( "Where ~> -[cos(x)| $\"pi\"$ /0]
\n" ); document.write( "-[cos( $\"pi\"$ ) - cos(0)]
\n" ); document.write( "-[-1 - 1]
\n" ); document.write( "-[-2]
\n" ); document.write( "Area is 2 units^2
\n" ); document.write( " $\"graph%28300%2C300%2C-1.6%2C4.8%2C-1%2C1%2Csin%28x%29%29\"$ \n" ); document.write( "

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