document.write( "Question 975934: Fred originally ran a 42km marathon in 3 hours. Fred wants to improve his net time by six minutes next year. He will try a different strategy of running for the first two hours at a certain (but unknown) speed, and then completing the rest of the race at a rate 2 kilometres per hour faster than this speed.\r
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document.write( "If he is to succeed, what is the speed will he need to run for the first two hours of next year’s marathon? \n" );
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Algebra.Com's Answer #597626 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Fred originally ran a 42km marathon in 3 hours. \n" ); document.write( " Fred wants to improve his net time by six minutes next year. \n" ); document.write( " He will try a different strategy of running for the first two hours at a certain (but unknown) speed, and then completing the rest of the race at a rate 2 kilometres per hour faster than this speed. \n" ); document.write( "If he is to succeed, what is the speed will he need to run for the first two hours of next year’s marathon? \n" ); document.write( ": \n" ); document.write( "Find the time (in hrs) of his improved time (6 min less than 3 hrs) \n" ); document.write( "2 + 54/60 = 2.9 hrs \n" ); document.write( ": \n" ); document.write( "Let s = his initial speed \n" ); document.write( "then \n" ); document.write( "(s+2) = finishing speed \n" ); document.write( ": \n" ); document.write( "Write a distance equation: dist = time * speed \n" ); document.write( ": \n" ); document.write( "initial speed dist + finishing speed dist = 42 km \n" ); document.write( "2s + .9(s+2) = 42 \n" ); document.write( "2s + .9s + 1.8 = 42 \n" ); document.write( "2.9s = 42 - 1.8 \n" ); document.write( "2.9s = 40.2 \n" ); document.write( "s = 40.2/2.9 \n" ); document.write( "s = 13.862 km/hr is his initial speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this by finding the actual dist at each speed. \n" ); document.write( "2(13.862) = 27.724 km \n" ); document.write( ".9(15.862) = 14.276 km (2km faster) \n" ); document.write( "---------------------- \n" ); document.write( "total dist: 42.000 km \n" ); document.write( " |