document.write( "Question 975770: A and B can do a piece of work in 6 days,B and c together in 10 days,c and A together in 7 1/2 days.in how many days can c individually completes the work?
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Algebra.Com's Answer #597542 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A and B can do a piece of work in 6 days,B and c together in 10 days,c and A together in 7 1/2 days.in how many days can c individually completes the work? \n" ); document.write( "*** \n" ); document.write( "let x=number of days A can individually complete the work \n" ); document.write( "1/x=his work rate \n" ); document.write( "let y=number of days B can individually complete the work \n" ); document.write( "1/y=his work rate \n" ); document.write( "let z=number of days C can individually complete the work \n" ); document.write( "1/z=his work rate \n" ); document.write( ".. \n" ); document.write( "1/x+1/y=1/6 (A & B) \n" ); document.write( "1/z+1/y=1/10 (C & B) \n" ); document.write( "1/x+1/z=1/7 (A & C) \n" ); document.write( ".. \n" ); document.write( "1/x+1/y=1/6 \n" ); document.write( "1/z+1/y=1/10 \n" ); document.write( "subtract: \n" ); document.write( "1/x-1/z=1/6-1/10=10/60-6/60=4/60=1/15 \n" ); document.write( "1/x-1/z=1/15 \n" ); document.write( ".. \n" ); document.write( "1/x-1/z=1/15 \n" ); document.write( "1/x+1/z=1/7 \n" ); document.write( "subtract: \n" ); document.write( "-2/z=1/15-1/7=7/105-15/105-8/105 \n" ); document.write( "8z=2*105=210 \n" ); document.write( "z=210/8=26.25 \n" ); document.write( "How many days can C individually completes the work? 26.25 \n" ); document.write( " |