document.write( "Question 975870: A and B are playing tag . A stay still while B runs from the same spot at a rate 2 meters per second. After 60 seconds B keeps running . A now runs after him at a rate of 3 meters per second. How long has A run when he caught up to B\r
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document.write( "My solution
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document.write( "3 (t-60) = 2t
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document.write( "3t - 180 =2t
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document.write( "3t-2t =180
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document.write( "t = 180 \n" );
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Algebra.Com's Answer #597541 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A and B are playing tag . A stay still while B runs from the same spot at a rate 2 meters per second. After 60 seconds B keeps running . A now runs after him at a rate of 3 meters per second. How long has A run when he caught up to B \n" ); document.write( "My solution \n" ); document.write( "3 (t-60) = 2t \n" ); document.write( "3t - 180 =2t \n" ); document.write( "3t-2t =180 \n" ); document.write( "t = 180 \n" ); document.write( "*** \n" ); document.write( "After 60 seconds, B has covered a distance=2*60=120 m \n" ); document.write( "3-2=1 m/sec=rate at which A is catching up to B \n" ); document.write( "A's travel time=120/1=120 seconds \n" ); document.write( "How long has A run when he caught up to B? 120 seconds \n" ); document.write( " |