document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4163>Question 4163</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in substitution how do you solve for a equation for x. then solve it for y? <BR>\n" );
document.write( "example 3x-5y=12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597531 by </B><A HREF=/tutors/aboutme.mpl?userid=kekegeter+><B>kekegeter (97)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kekegeter+><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=kekegeter+><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For x\r<BR>\n" );
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document.write( "3x-5y=12\r<BR>\n" );
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document.write( "3x=5y+12\r<BR>\n" );
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document.write( "x=5y+12/3\r<BR>\n" );
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document.write( "For y\r<BR>\n" );
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document.write( "3x-5y=12\r<BR>\n" );
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document.write( "-5y= -3x+12\r<BR>\n" );
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document.write( "y= -3(-x+4)/5<BR>\n" );
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