document.write( "Question 975836: evaulate the piecewise function.
\n" ); document.write( "f(x)=
\n" ); document.write( "6 if x ≤3
\n" ); document.write( "3x-5 if x > 3
\n" ); document.write( "f(-4)=
\n" ); document.write( "f(0)=
\n" ); document.write( "f(3)=
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\n" ); document.write( "f(6)=
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Algebra.Com's Answer #597491 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The piecewise function basically breaks down into\r
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\n" ); document.write( "\n" ); document.write( "f(x) = 6 if x <= 3
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\n" ); document.write( "f(x) = 3x-5 if x > 3\r
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\n" ); document.write( "\n" ); document.write( "f(-4) = 6
\n" ); document.write( "because x = -4, which is less than or equal to 3, this means we use the first definition of f(x) above\r
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\n" ); document.write( "\n" ); document.write( "f(0) = 6
\n" ); document.write( "x = 0 makes x <=3 true
\n" ); document.write( "same reasoning as f(-4)\r
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\n" ); document.write( "\n" ); document.write( "f(3) = 6
\n" ); document.write( "same reasoning as f(0) and f(-4) above\r
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\n" ); document.write( "\n" ); document.write( "f(x) = 3x - 5
\n" ); document.write( "f(4) = 3*4 - 5
\n" ); document.write( "f(4) = 7
\n" ); document.write( "now we use the second definition since x = 4 makes x > 3 true.\r
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\n" ); document.write( "\n" ); document.write( "f(x) = 3x - 5
\n" ); document.write( "f(6) = 3*6 - 5
\n" ); document.write( "f(6) = 13
\n" ); document.write( "we use the second definition since x = 6 makes x > 3 true.\r
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\n" ); document.write( "\n" ); document.write( "If you need more one-on-one help, email me at jim_thompson5910@hotmail.com. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).\r
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\n" ); document.write( "\n" ); document.write( "Jim\r
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