document.write( "Question 975820: A petroleum company has two different sources of crude oil. The first source provides crude oil that is
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document.write( "50%
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document.write( " hydrocarbons, and the second one provides crude oil that is
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document.write( "75%
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document.write( " hydrocarbons. In order to obtain
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document.write( "140
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document.write( " gallons of crude oil that is
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document.write( "60%
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document.write( " hydrocarbons, how many gallons of crude oil must be used from each of the two sources?
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document.write( "
Algebra.Com's Answer #597479 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A petroleum company has two different sources of crude oil. The first source provides crude oil that is 50% hydrocarbons, and the second one provides crude oil that is 75% hydrocarbons. \n" ); document.write( "In order to obtain 140 gallons of crude oil that is 60% hydrocarbons, how many gallons of crude oil must be used from each of the two sources? \n" ); document.write( "------------ \n" ); document.write( "Equation:: \n" ); document.write( "carbon + carbon = carbon \n" ); document.write( "----------- \n" ); document.write( "0.50x + 0.75(140-x) = 0.60*140 \n" ); document.write( "----------- \n" ); document.write( "50x + 75*140 - 75x = 60*140 \n" ); document.write( "----------- \n" ); document.write( "-25x = -15*140 \n" ); document.write( "x = (3/5)140 \n" ); document.write( "------ \n" ); document.write( "x = 3*28 \n" ); document.write( "x = 84 gallons (amt of 50% oil needed) \n" ); document.write( "---- \n" ); document.write( "140-x = 56 gallons (amt of 75% oil needed) \n" ); document.write( "------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " |