document.write( "Question 975814: Due to melting, an ice sculpture loses half of its weight every hour. After eight hours, it weighs 5/16 of a pound. How much did it weigh in the beginning?\r
\n" ); document.write( "\n" ); document.write( "I have tried...1/2x-60=8(5/16) I do not know how to set up the equation? \n" ); document.write( "
Algebra.Com's Answer #597456 by Alan3354(69443)\"\" \"About 
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Due to melting, an ice sculpture loses half of its weight every hour. After eight hours, it weighs 5/16 of a pound. How much did it weigh in the beginning?\r
\n" ); document.write( "\n" ); document.write( "I have tried...1/2x-60=8(5/16) I do not know how to set up the equation?
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\n" ); document.write( "W = starting weight.
\n" ); document.write( "L = weight left.
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\n" ); document.write( "L = W*(1/2)^t (t in hours)
\n" ); document.write( "5/16 = W*(1/2)^8 = W/256
\n" ); document.write( "W = (5/16)*256 = 80 pounds.
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\n" ); document.write( "Start: 80 pounds
\n" ); document.write( "> 1 hr 40 pounds
\n" ); document.write( "> 2 hr 20 pounds
\n" ); document.write( "> 3 hr 10 pounds
\n" ); document.write( "> 4 hr 5 pounds
\n" ); document.write( "> 5 hr 5/2 pounds
\n" ); document.write( "> 6 hr 5/4 pounds
\n" ); document.write( "> 7 hr 5/8 pounds
\n" ); document.write( "> 8 hr 5/16 pounds
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