document.write( "Question 975681: Use the given information to evaluate each expression. (Enter your answers in exact form.)
\n" ); document.write( "cos β = −2/7 with 180° < β < 270°
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Algebra.Com's Answer #597393 by ikleyn(52797)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Use the formulas for trigonometric functions of half argument  (see,  for example,  the lesson  FORMULAS FOR TRIGONOMETRIC FUNCTIONS  in this site)\r
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\n" ); document.write( "\n" ); document.write( "\"sin%28beta%2F2%29\" = \"sqrt%28%281-cos%5E2%28beta%29%29%2F2%29\" = \"sqrt%28%281-%28%28-2%29%2F7%29%5E2%29%2F2%29\" = \"sqrt%28%281-%284%2F49%29%29%2F2%29\" = \"sqrt%28%28%2849-4%29%2F49%29%2F2%29\" = \"sqrt%2845%2F%2849%2A2%29%29\" = \"%283%2F7%29%2Asqrt%285%2F2%29\" = \"%283%2F7%29%2A%281%2F2%29%2Asqrt%2810%29\" = \"%283%2F14%29%2Asqrt%2810%29\". \r
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\n" ); document.write( "\n" ); document.write( "\"cos%28beta%2F2%29\" = \"-sqrt%28%281%2Bcos%5E2%28beta%29%29%2F2%29\" = \"-sqrt%28%281%2B%28%28-2%29%2F7%29%5E2%29%2F2%29\" = \"-sqrt%28%281%2B%284%2F49%29%29%2F2%29\" = \"-sqrt%28%28%2849%2B4%29%2F49%29%2F2%29\" = \"-sqrt%2853%2F%2849%2A2%29%29\" = \"-%281%2F7%29%2Asqrt%2853%2F2%29\" = \"-%281%2F7%29%2A%28sqrt%28106%29%2F2%29\" = \"-%281%2F14%29%2Asqrt%28106%29\"\r
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\n" ); document.write( "\n" ); document.write( "                    (the sign  \"minus\"  because the angle  \"beta%2F2\"  is in the 2-nd quadrant). \r
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\n" ); document.write( "\n" ); document.write( "\"tan%28beta%2F2%29\" = \"sin%28beta%2F2%29%2Fcos%28beta%2F2%29\" = \"-%28%283%2A14%29%2F14%29%2A%28sqrt%2810%29%2Fsqrt%28106%29%29\" = \"-3%2A%28sqrt%2810%29%2Fsqrt%28106%29%29\".\r
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