document.write( "Question 975557: Nadia leaves San Francisco at noon. Deena leaves San Francisco at 12:30pm. Deena is traveling 16 mph faster than Nadia. If Deena passes Nadia at 2:00pm, how fast are they each going? \n" ); document.write( "
Algebra.Com's Answer #597392 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Nadia leaves San Francisco at noon. Deena leaves San Francisco at 12:30pm. Deena is traveling 16 mph faster than Nadia. If Deena passes Nadia at 2:00pm, how fast are they each going? \n" ); document.write( "*** \n" ); document.write( "let x=Nadia's speed \n" ); document.write( "Nadia's travel time=12 noon to 2 pm=2 hours \n" ); document.write( "x+16=Deena's speed \n" ); document.write( "Deena's travel time=12:30 noon to 2 pm=1.5 hours \n" ); document.write( "distance=travel time*speed (same for both) \n" ); document.write( ".. \n" ); document.write( "2x=1.5(x+16) \n" ); document.write( "2x=1.5x+24 \n" ); document.write( ".5x=24 \n" ); document.write( "x=48 \n" ); document.write( "x+16=64 \n" ); document.write( "how fast are they each going? \n" ); document.write( "Nadia's speed=48 mph \n" ); document.write( "Deena's speed=64 mph \n" ); document.write( " |