document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=975654>Question 975654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation by expressing each side as a power of the same base and then equating exponents?\r<BR>\n" );
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document.write( "125^x = 1/sqaure root(5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597356 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the equation by expressing each side as a power of the same base and then equating exponents? <BR>\n" );
document.write( "125^x = 1/sqaure root(5)<BR>\n" );
document.write( "(5^3)^x=1/5^(1/2)<BR>\n" );
document.write( "5^3x=5^(-1/2)<BR>\n" );
document.write( "3x=-1/2<BR>\n" );
document.write( "x=-1/6 </SPAN>\n" );
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