document.write( "Question 83203: find the center and radius of the circle
\n" ); document.write( "3x^2+4y^2-6x+4y-4=0
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Algebra.Com's Answer #59735 by jim_thompson5910(35256)\"\" \"About 
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\"3x%5E2%2B4y%5E2-6x%2B4y-4=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2B4y%5E2-6x%2B4y=4\" add 4 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%5E2-6x%29%2B%284y%5E2%2B4y%29=4\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2-2x%29%2B4%28y%5E2%2By%29=4\" Factor out the GCF\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2-2x%2B1%29%2B4%28y%5E2%2By%2B1%2F4%29=4%2B3%2B1\" Complete the squares of each parenthesis (remember to add to both sides)\r
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\n" ); document.write( "\n" ); document.write( "Since we completed the squares, we get\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x-1%29%5E2%2B4%28y%2B1%2F2%29%5E2=8\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283%28x-1%29%5E2%2B4%28y%2B1%2F2%29%5E2%29%2F8=8%2F8\" Now divide both sides by 4 to get the equation into standard form \"%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x-1%29%5E2%2F8%2B%28y%2B1%2F2%29%5E2%2F2=1\"\r
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\n" ); document.write( "\n" ); document.write( "So the equation is actually an ellipse (check your problem again) where the radii are \"sqrt%288%2F3%29\" and \"sqrt%282%29\" and the center is (1,\"-1%2F2\")
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