document.write( "Question 975628: Given log base 8 {xy} = 3, find x and y. I've found that it becomes xy = 3^8, therefore xy = 512, but after that what should I do? Thank you tutors for making time to help me! \n" ); document.write( "
Algebra.Com's Answer #597341 by Edwin McCravy(20067) You can put this solution on YOUR website! \r\n" ); document.write( "\r\n" ); document.write( "Actually it's 83 not 38.\r\n" ); document.write( "\r\n" ); document.write( "The base of the log is the base of the exponent. \r\n" ); document.write( "\r\n" ); document.write( "log8(xy) = 3\r\n" ); document.write( "\r\n" ); document.write( "becomes the equation\r\n" ); document.write( "\r\n" ); document.write( "xy = 83\r\n" ); document.write( "\r\n" ); document.write( "xy = 512 <-- so you had 512, so you must have had 83, not 38.\r\n" ); document.write( "\r\n" ); document.write( "There are many solutions to that. There are infinitely many. Maybe\r\n" ); document.write( "you were to find just the positive integer solutions. If so,\r\n" ); document.write( "the solution (x,y) could be any of these:\r\n" ); document.write( "\r\n" ); document.write( "(1,512) (2,256) (4,128) (8,64) (16,32) (32,16) (64,8) (128,4) (256,2) (512,1)\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |