document.write( "Question 83206: Apply the formulas for motion due to gravitational attraction.\r
\n" ); document.write( "\n" ); document.write( " A stone is dropped from the top of a building 240 feet high. It is observed to take 0.20 seconds to go past an office floor-to-ceiling window that is 12 feet high. How far is it from the bottom of the window down to the street?
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Algebra.Com's Answer #59733 by stanbon(75887)\"\" \"About 
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A stone is dropped from the top of a building 240 feet high. It is observed to take 0.20 seconds to go past an office floor-to-ceiling window that is 12 feet high. How far is it from the bottom of the window down to the street?
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\n" ); document.write( "S(t) = -16t^2+240
\n" ); document.write( "Velocity = -32t ft/sec
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\n" ); document.write( "Velocity of the stone while passing the window:
\n" ); document.write( "-12ft/0.2 sec = -60 ft/sec
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\n" ); document.write( "Therefore:
\n" ); document.write( "-32t =-60
\n" ); document.write( "t= 1.875 seconds
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\n" ); document.write( "So, where is the stone at t=1.875 sec ?
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\n" ); document.write( "s(1.875) = -32(1.875)^2+240
\n" ); document.write( "s(1.875) = 127.5 ft above the ground
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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