document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=975534>Question 975534</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve 5y-y+1/3=y+1/4+y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597273 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5y-y+1/3=y+1/4+y\r<BR>\n" );
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document.write( "Collect terms<BR>\n" );
document.write( "4y+(1/3)=2y+(1/4)  ;;isolate y on one side and numbers on other.<BR>\n" );
document.write( "2y=(-1/12)  ;; now divide by 2.<BR>\n" );
document.write( "y=(-1/24)\r<BR>\n" );
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document.write( "Check (-4/24)+(1/3)=(-2/24)+(1/4)<BR>\n" );
document.write( "Both = (1/6) </SPAN>\n" );
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