document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=975497>Question 975497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to find the quadratic function of a parabola with a vertex of 5.3 and X intercepts -5.25 and 5.25 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597266 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597266\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ordered pair for the vertex is (0,5.3) because its x coordinate is in the middle of the zeros' values.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=a%28x-0%29%5E2%2B5.3 ALIGN=MIDDLE  ALT=\"y=a%28x-0%29%5E2%2B5.3\"   DISABLED_style= \"max-width:90%; height:auto;\" >, full standard form<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=ax%5E2%2B5.3 ALIGN=MIDDLE  ALT=\"y=ax%5E2%2B5.3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Solve for a<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-5.3=ax%5E2 ALIGN=MIDDLE  ALT=\"y-5.3=ax%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28y-5.3%29%2Fx%5E2=a ALIGN=MIDDLE  ALT=\"%28y-5.3%29%2Fx%5E2=a\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Substitute either of the given zeros to have an expression for a<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=%280-5.3%29%2F%285.25%29%5E2 ALIGN=MIDDLE  ALT=\"a=%280-5.3%29%2F%285.25%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=5.3%2F5.25%5E2 ALIGN=MIDDLE  ALT=\"a=5.3%2F5.25%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=0.193333cross%283repeating%29 ALIGN=MIDDLE  ALT=\"a=0.193333cross%283repeating%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "which could really be expressed as a rational number, but if your 5.3 was a measurement<BR>\n" );
document.write( "then a good choice could well be more like a=0.193.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y=%280.193%29x%5E2%2B5.3%29 ALIGN=MIDDLE  ALT=\"highlight%28y=%280.193%29x%5E2%2B5.3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "a might in fact NOT be a repeating decimal in the way I thought first, but using <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1=16%2F16 ALIGN=MIDDLE  ALT=\"1=16%2F16\"   DISABLED_style= \"max-width:90%; height:auto;\" >, you should be able to find <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=848%2F4410 ALIGN=MIDDLE  ALT=\"a=848%2F4410\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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