document.write( "Question 975459: you have 52 coins consisting of dimes and nickels the coins total $3.55 how many are dimes how many are nickles? \n" ); document.write( "

Algebra.Com's Answer #597264 by Edwin McCravy(20060) $\"\"$ $\"About$

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document.write( "Let the number of dimes be x\r\n" );
document.write( "Then the number of nickels, using\r\n" );
document.write( "ONE PART = TOTAL MINUS OTHER PART,\r\n" );
document.write( "is 52-x.\r\n" );
document.write( "                      Value      Value\r\n" );
document.write( "Type       Number       of         of\r\n" );
document.write( " of          of        EACH       ALL\r\n" );
document.write( "coin        coins      coin      coins\r\n" );
document.write( "-------------------------------------------\r\n" );
document.write( "dimes         x       $0.10     $0.10x\r\n" );
document.write( "nickels    52-x       $0.05     $0.05(52-x)\r\n" );
document.write( "-------------------------------------------\r\n" );
document.write( "TOTALS      52        -----     $3.55\r\n" );
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document.write( " The equation comes from the column on the right\r\n" );
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document.write( "  \r\n" );
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document.write( "0.10x + 0.05(52-x) = 3.55\r\n" );
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document.write( "Get rid of decimals by multiplying every term by 100:\r\n" );
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document.write( "     10x + 5(52-x) = 355\r\n" );
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document.write( "    10x + 260 - 5x = 355\r\n" );
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document.write( "          5x + 260 = 355\r\n" );
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document.write( "                5x = 95\r\n" );
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document.write( "                 x = 19 = the number of dimes.\r\n" );
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document.write( "The number of nickels is 52-x or 52-19 or 33 nickels.\r\n" );
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document.write( "Checking:  19 dimes is $1.90 and 33 nickels is $1.65\r\n" );
document.write( "            That's 52 coins.\r\n" );
document.write( "            And indeed $1.90 + $1.65 = $3.55\r\n" );
document.write( "Edwin

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