document.write( "Question 975494: A money box contains only 10-cent and
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\n" ); document.write( "\n" ); document.write( "I worked out the answer by guessing easily enough, but now I want to know if there is an algebraic approach to this?
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Algebra.Com's Answer #597259 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Let represent the number of 10 cent coins and represent the number of 20 cent coins. The total number of coins is 25, so:\r
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\n" ); document.write( "\n" ); document.write( "The 10 cent coins, being worth 10 cents each, must have a value of cents if there are of them. Likewise, the value of 20 cent coins is cents. The sum of these two values is 350 cents.\r
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\n" ); document.write( "\n" ); document.write( "Would work just as well, but decimals are always messier than whole numbers, and neatness helps avoid errors.\r
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\n" ); document.write( "\n" ); document.write( "So now all you need to do is solve the 2X2 linear system for and . This is a fairly straight-forward 2X2 system and either the substitution or the elimination method should work well enough.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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