document.write( "Question 83193This question is from textbook introductory algebra
\n" ); document.write( ": Rowing with the current of a river, a rowing team can row 25 miles in the same amount of time it takes to row 15 miles against the current. The rate of the rowing team in calm water is 20 mph. Find the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #59714 by stanbon(75887)\"\" \"About 
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Rowing with the current of a river, a rowing team can row 25 miles in the same amount of time it takes to row 15 miles against the current. The rate of the rowing team in calm water is 20 mph. Find the rate of the current
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\n" ); document.write( "With current DATA:
\n" ); document.write( "Distance = 25 mi ; Rate = c+20 mph ; Time = 25/(c+20)
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\n" ); document.write( "Against current DATA:
\n" ); document.write( "Distance = 15 mi ; Rate = 20-c mph ; Time = 15(20-c)
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\n" ); document.write( "EQUATION:
\n" ); document.write( "time with = time against
\n" ); document.write( "25/(c+20) = 15/(20-c)
\n" ); document.write( "5/(c+20) = 3/(20-c)
\n" ); document.write( "100-5c = 3c+60
\n" ); document.write( "8c = 40
\n" ); document.write( "c= 5 mph ( rate of current)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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