document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83193>Question 83193</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618203230/algebrahomeworkh>introductory algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Rowing with the current of a river, a rowing team can row 25 miles in the same amount of time it takes to row 15 miles against the current. The rate of the rowing team in calm water is 20 mph. Find the rate of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59713 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> time=distance/rate<BR>\n" );
document.write( "seeing as the times are the same we have the following equation:<BR>\n" );
document.write( "15/(20-c)=25/(20+c) c=current. now cross multiply.<BR>\n" );
document.write( "15(20+c)=25(20-c)<BR>\n" );
document.write( "300+15c=500-25c<BR>\n" );
document.write( "15c+25c=500-300<BR>\n" );
document.write( "40c=200<BR>\n" );
document.write( "c=200/40<BR>\n" );
document.write( "c=5 rate of the current.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "15/(20-5)=25/(20+5)<BR>\n" );
document.write( "15/15=25/25<BR>\n" );
document.write( "1=1  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );