document.write( "Question 975361: (3x+5)/(x+5)-(x+1)/(2-x)-(4x^2-3x-1)/(x^2+3x-10)
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Algebra.Com's Answer #597125 by Boreal(15235)\"\" \"About 
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(3x+5)/(x+5) + (x+1)/(x-2) - [(4x^2-3x-1)/(x+5)(x-2)]\r
\n" ); document.write( "\n" ); document.write( "I did two things here. I changed the sign of the second term and made the denominator (x-2)
\n" ); document.write( "I did not factor the numerator after the minus sign, but I did factor the denominator. Note that I can add these if I use a common denominator of (x+5) and (x-2). The first two terms will change, but not the last. Then I can subtract\r
\n" ); document.write( "\n" ); document.write( "(3x+5) (x-2)=3x^2-x-10
\n" ); document.write( "(x+1)(x+5)=x^2+6x+5
\n" ); document.write( "These two will be the first two terms over the common denominator.\r
\n" ); document.write( "\n" ); document.write( "Ignoring for the moment the common denominator, we combine terms, subtracting 4x^2-3x-1, and all terms will change signs.\r
\n" ); document.write( "\n" ); document.write( "3x^2-x-10+x^2+6x+5-4x^2+3x+1\r
\n" ); document.write( "\n" ); document.write( "The x^2 cancel.
\n" ); document.write( "-x-10+6x+5+3x+1
\n" ); document.write( "This is 8x-4= 4(2x-1)\r
\n" ); document.write( "\n" ); document.write( "That is over the common denominator of (x+5)(x-2)\r
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\n" ); document.write( "\n" ); document.write( "4(2x-1)/(x+5)(x-2)\r
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